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Projectile Motion & Ballistic Trajectory Calculator

Simulate 2D projectile kinematics with arbitrary initial height, launch speed, angle, and planetary gravity. Calculates apex elevation, total flight time, horizontal range, and impact velocity with scalable vector trajectory plotting.

Launch Angle (θ): 45°
Total Horizontal Range
63.73 m
209.1 Feet
Maximum Apex Height
15.93 m
52.3 Feet (Peak Elevation)
Total Flight Time
3.60 s
Apex reached at 1.80 s
Impact Velocity
25.00 m/s
Impact Angle: -45.0°

📈 Ballistic Parabolic Trajectory Curve

Vector schematic drawn to exact mathematical scale showing initial launch vector, trajectory apex peak, and landing range coordinate.

📐 Step-by-Step Classical Kinematics Derivations

Solving kinematic motion equations...

⚠️ 5 Fatal Traps & Physics Misunderstandings in Ballistics

1. The "45 Degrees is Always Maximum Range" Fallacy High school physics students memorize that 45° produces maximum range. This is true ONLY when launch height equals landing height ($y_0 = 0$). When throwing from a cliff, standing height, or aircraft ($y_0 > 0$), the optimal angle is strictly less than 45°: $\theta = \arcsin(1 / \sqrt{2 + 2gy_0/v_0^2})$. In shot put (release height 2.1m), optimal launch angle is roughly 37°–38°.
2. Neglecting Aerodynamic Drag in Real-World Athletics In baseball, golf, or artillery, atmospheric drag forces ($F_d = \frac{1}{2}\rho v^2 C_d A$) alter trajectories radically. A 100 mph baseball hit in a vacuum travels over 700 feet; with air drag and Magnus spin backspin, it travels roughly 400 feet and exhibits an asymmetric trajectory with a steep, abrupt terminal drop.
3. JavaScript Radians vs. Degrees Calculation Bug JavaScript math functions (Math.sin(), Math.cos()) strictly expect angles in radians. Passing raw degrees without converting $ heta_{ ext{rad}} = heta_{ ext{deg}} imes (pi / 180)$ generates nonsensical negative flight times and negative ranges.
4. Overlooking Kinetic Energy Transformation at Apex At the trajectory apex, vertical velocity reaches zero ($v_y = 0$), but kinetic energy is NOT zero. The projectile still retains 100% of its horizontal kinetic energy: $E_k = \frac{1}{2}m v_x^2 = \frac{1}{2}m (v_0 \cos\theta)^2$. Only in a purely vertical 90° launch does kinetic energy drop to absolute zero at peak.
5. Coriolis Acceleration in Long-Range Ballistics (>1,000m) For extreme long-range rifle shooting and naval artillery, Earth rotates beneath the projectile during its multi-second flight. In the Northern Hemisphere, the Coriolis acceleration deflects trajectories to the right by several inches to feet depending on target latitude and azimuth.
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